Comments on: an airplane, flying in the direction of 40degree east of north at 475 mph in still air, encounter a 30-mph tai? http://airtim.es/airplane-flying/an-airplane-flying-in-the-direction-of-40degree-east-of-north-at-475-mph-in-still-air-encounter-a-30-mph-tai Thu, 18 Feb 2010 13:05:59 -0600 http://wordpress.org/?v=abc hourly 1 By: Messiah's Mistress http://airtim.es/airplane-flying/an-airplane-flying-in-the-direction-of-40degree-east-of-north-at-475-mph-in-still-air-encounter-a-30-mph-tai/comment-page-1#comment-3640 Messiah's Mistress Wed, 04 Nov 2009 19:24:59 +0000 http://airtim.es/airplane-flying/an-airplane-flying-in-the-direction-of-40degree-east-of-north-at-475-mph-in-still-air-encounter-a-30-mph-tai#comment-3640 http://www.youtube.com/watch?v=eBgLvN10ufA&NR=1<br><b>References : </b><br> http://www.youtube.com/watch?v=eBgLvN10ufA&NR=1
References :

]]> By: M http://airtim.es/airplane-flying/an-airplane-flying-in-the-direction-of-40degree-east-of-north-at-475-mph-in-still-air-encounter-a-30-mph-tai/comment-page-1#comment-3639 M Wed, 04 Nov 2009 19:16:59 +0000 http://airtim.es/airplane-flying/an-airplane-flying-in-the-direction-of-40degree-east-of-north-at-475-mph-in-still-air-encounter-a-30-mph-tai#comment-3639 V_g = V_a + V_w V_g = speed over ground V_a = airspeed V_w = wind speed V_a = V sin(40) i + V cos(40) j; V = 475 mph V_w = - W sin(40) i + W cos(40) j; W = 30 mph V_g = (V - W) sin(40) i + (V+W) cos(40) j = Vx i + Vy j Speed = sqrt(Vx^2 + Vy^2) Direction angle = 90 - atan(Vy/Vx)<br><b>References : </b><br> V_g = V_a + V_w

V_g = speed over ground
V_a = airspeed
V_w = wind speed

V_a = V sin(40) i + V cos(40) j; V = 475 mph
V_w = – W sin(40) i + W cos(40) j; W = 30 mph

V_g = (V – W) sin(40) i + (V+W) cos(40) j = Vx i + Vy j

Speed = sqrt(Vx^2 + Vy^2)

Direction angle = 90 – atan(Vy/Vx)
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