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Nov 042009

an airplane, flying in the direction of 40degree east of north at 475 mph in still air, encounter a 30-mph tai?

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an airplane, flying in the direction of 40degree east of north at 475 mph in still air, encounter a 30-mph tail wind acting in the direction 40degree west of north. the airplane maintains its compass heading but, because of the wind, acquires a new ground speed and direction. what are they?
whats the new ground speed?
whats is the new direction angle (thats east of north)?

thank you

http://www.youtube.com/watch?v=eBgLvN10ufA&NR=1

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Posted by Airtime at 8:26 am Tagged with: Acting, airplane, Amp, Compass Heading, encounter, Ground Speed, New Direction, New Ground, Nr, Tail Wind, Whats New, Wind Direction, Wind Speed

2 Responses to “an airplane, flying in the direction of 40degree east of north at 475 mph in still air, encounter a 30-mph tai?”

  1. M says:
    November 4, 2009 at 2:16 pm

    V_g = V_a + V_w

    V_g = speed over ground
    V_a = airspeed
    V_w = wind speed

    V_a = V sin(40) i + V cos(40) j; V = 475 mph
    V_w = – W sin(40) i + W cos(40) j; W = 30 mph

    V_g = (V – W) sin(40) i + (V+W) cos(40) j = Vx i + Vy j

    Speed = sqrt(Vx^2 + Vy^2)

    Direction angle = 90 – atan(Vy/Vx)
    References :

  2. Messiah's Mistress says:
    November 4, 2009 at 2:24 pm

    http://www.youtube.com/watch?v=eBgLvN10ufA&NR=1
    References :

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